Question

10 years ago age of father was four times that of his son .5years ago the age of father was three times that of his son find the present ages of father and son

Answer 1

Let, age of father = x
Age of son = y
By first condition,
x - 10 = 4(y-10)
x - 10 = 4y - 40
x - 4y = - 40 + 10
i.e. x - 4y = - 30..... (1)
By second condition,
x - 5 = 3(y-5)
x - 5 = 3y - 15
x - 3y = - 15 + 5
i.e. x - 3y = - 10..... (2)
Subtracting eqn. (2) from (1), we get
x - 4y - ( x - 3y) = - 30 - (-10)
x - 4y - x + 3y = - 30 + 10
-y = - 20
y = 20

Putting value of y in eqn(2),
x - 3y = - 10
x - 3 × 20 = - 10
x - 60 = - 10
x = - 10 + 60
x = 50
Therefore present ages of father and son are 50 years and 20 years respectively.

Answer 2

Hope this will Help u Dear

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