Question

10 years ago As age was half of Bs age. if the ratio of their ages is 3:4 find the sum of their present ages​

Answer 1

Let A's age 10 years ago = x years.

Then, B's age 10 years ago = 2x years.

(x + 10) / (2x+ lO) = 3/4

=> x = 5.

So, the total of their present ages =(x + 10 + 2x + 10)

= (3x + 20) = 35 years.