Question

10 Years ago B was twice of A age if the ratio of their present age is 4:3 what is the sum of their present age ?

Answer 1

Answer:

Sum Of Their Present Age = 35 years

Step-by-step explanation:

Let 10 years age A age = x years

Then age of B at that time = 2x years

Current age of A = x + 10 years

Current age of B = 2x + 10

According to the question

2x + 10/x + 10 = 4/3

3(2x + 10) = 4(x + 10)

6x + 30 = 4x + 40

6x - 4x = 40 - 30

2x = 10

x = 5 years

Therefore current age of A = 10+5

= 15 years

And that of B = 20 years

Sum of their age = 15 + 20 = 35 years

Answer 2

Find the answer in the attached picture.

Hope this helps!