Math, asked by pavithrachawhan053, 9 months ago

10 years ago father age was 12 times as
old as his sons age and 10 years hence father age is
twice his son age

Answers

Answered by Anonymous
2

Answer:

34 years

Step-by-step explanation:

Ten years ago father was 12 times as old as his son at that time

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)⇒2x+40=12x+20

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)⇒2x+40=12x+20⇒10x=20

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)⇒2x+40=12x+20⇒10x=20 ⇒x=2

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)⇒2x+40=12x+20⇒10x=20 ⇒x=2 ⇒ age of son at present=x+10=2+10=12

Ten years ago father was 12 times as old as his son at that timeLet the age of the son before 10 years =x and age of the father before 10 years =12x10 years hence he will be twice as old as his son.2(x+10+10)=(12x+10+10)⇒2x+40=12x+20⇒10x=20 ⇒x=2 ⇒ age of son at present=x+10=2+10=12Age of the father at present=12x+10=122+10=34

Hope it helps you

Answered by amitheshbettin
0

2 year

Step-by-step explanation:

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