Question

10 years ago father was 12 time as old as his son and 10 years hence, he will be twice as old as his son. find their present age
​

Answer 1

Answer:

father 34 yr son 12 yr

Step-by-step explanation:

let father be of x yr & son y yr

as per given data

x-10 = 12 ( y-10) &

x+10 = 2 (y+10)

solving

x-12y =. - 110 &

x-2y = 10

solving

x= 34 father & y =12

cross. check

before 10 yr father was 24 & son 2 yr

after 10 yrs father will be 44 & son 22 yrs

as per data.