Question

10 years ago father was 12 times as old as her daughter in 10 years he will be twice as old as her daughter will be find their present ages

Answer 1

Answer:


Step-by-step explanation:


Let the age of daughter be x


Let the age of father be 12x


Before 10 years, age of daughter = x - 10 and age of her father = 12x - 10


After 10 years, age of daughter = x + 10 and age of father = 2(x + 10)



According to the question,


x - 10 + 12x - 10 = x + 10 + 2(x + 10)


=> 13x - 20 = x + 10 + 2x + 20


=> 13x - 20 = 3x + 30


=> 13x - 3x = 30 + 20


=> 10x = 50


=> x = 50/10


=> x = 5




\therefore{}∴ Age of daughter => x


=> 5 years



\therefore{}∴ Age of father => 12x


=> 12 * 5


=> 60 years

Answer 2

Answer:

father age=34 years old

daughter age=12 years old

Step-by-step explanation:

let the age of father and daughter be x and y respectively.

CASE 1

x-10=12(y-10)

or,x-10=12y-120

or,x-12y=-120+10

or,x-12y=-110

or,x=-110+12y-(i)

CASE 2

x+10=2(y+10)

or,x+10=2y+20

or,x-2y=20-10

or,x-2y=10-(ii)

Now ,putting the value of x from eq-(i) in eq-(i)

-110+12y-2y=10

or,10y=10+110

or,10y=120

or,y=120/10

therefore, y=12

again,putting the value of y in eq-(i)

  x=-110+12*12

or,x=-110+144

therefore, x=34

hence, father is 34 years old and daughter is 12 years old.

hope it is helpful for you!!!

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