Question

10 years ago father was 12 times as old as his son. after 10 years father will be twice as old as his son.the present age of father is?​

Answer 1

Let the age of son be x years .

Let the age of father be y years .

A.T.Q

$(y - 10) = 12(x - 10) \\ y - 10 = 12x - 120 \\ - 12x + y + 110 = 0 \\ y = 12x - 110 \: \: ......(1) \\ \\ (y +10) = 2(x + 10) \\ y + 10 = 2x + 20 \\ using \: (1) \\ 12x - 110 + 10 = 2x + 20 \\ 12x - 2x - 100 - 20 = 0 \\ 10x - 120 = 0 \\ 10(x - 12) = 0 \\ x = 12 \\ \\ putting \: the \: value \: in \: (1) \\ y = 12(12) - 110 \\ y = 144 - 110 \\ y = 34$

Age of son = 12 years

Age of father = 34 years