Question

10 years ago father was 12 times as old as his son
and 10 year hence he will
be twice as old as his son will be
find their present ages​

Answer 1

Answer:

Ten years ago father was 12 times as old as his son at that time

Let the age of the son before 10 years =x and age of the father before 10 years =12x

10 years hence he will be twice as old as his son.

2(x+10+10)=(12x+10+10)

⇒2x+40=12x+20

⇒10x=20

⇒x=2

⇒ age of son at present=x+10=2+10=12

Age of the father at present=12x+10=122+10=34

Answer 2

Answer:

˙❥˙ᴘʀᴇꜱᴇɴᴛ ᴀɢᴇ ᴏꜰ ꜱᴏɴ = 12 ʏᴇᴀʀꜱ

˙❥˙ᴘʀᴇꜱᴇɴᴛ ᴀɢᴇ ᴏꜰ ꜰᴀᴛʜᴇʀ = 34 ʏᴇᴀʀꜱ

Step-by-step explanation:

ʟᴇᴛ ,

ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴀɢᴇ ᴏꜰ ꜱᴏɴ = x ʏᴇᴀʀꜱ

ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴀɢᴇ ᴏꜰ ꜰᴀᴛʜᴇʀ = ʏ ʏᴇᴀʀꜱ

ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴛʜᴇ ᴄᴏɴᴅɪᴛɪᴏɴꜱ ,

ʏ - 10 = 12 (x - 10) → 12x - ʏ = 110 ... 1)

ʏ + 10 = 2 (x + 10) → 2x - ʏ = -10 ...2)

ꜱᴜʙᴛʀᴀᴄᴛɪɴɢ 2) ꜰʀᴏᴍ 1) , ᴡᴇ ɢᴇᴛ

⭑x = 12⭑

ꜱᴜʙᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ x = 12 ɪɴ ᴇQᴜᴀᴛɪᴏɴ 2) , ᴡᴇ ɢᴇᴛ

2 (12) - ʏ = -10

24+10 = ʏ

⭑ʏ = 34⭑

✧*。ᴛʜᴇʀᴇꜰᴏʀᴇ ᴛʜᴇ ᴘʀᴇꜱᴇɴᴛ ᴀɢᴇ ᴏꜰ ꜱᴏɴ ᴀɴᴅ ꜰᴀᴛʜᴇʀ ɪꜱ 12 ʏᴇᴀʀꜱ ᴀɴᴅ 34 ʏᴇᴀʀꜱ ʀᴇꜱᴘᴇᴄᴛɪᴠᴇʟʏ .✧*

⭐❤️ hope it's help you ❤️⭐