Question

10 years ago father was 12 times as old as his son and 10 years hence he will be twice as old as his son.find their present ages

Answer 1

let the present age of Son be x years
let the present age of father be y years
ATQ,
$12(x - 10) = y - 10 \\ 12x - 120 = y - 10 \\ 12x - y = - 10 + 120 \\ 12x - y = 110 \\ let \: it \: be \: equation \: no. \: 1 \\ \\ case2 \\ 2(x + 10 = y + 10 \\ 2x + 20 = y + 10 \\ 2x - y = - 10 \\ let \: itbe \: equation \: no.2 \\ \\ from \: 1and2 \\ \\ subtractimg \: 1 \: and \: 2 \: weget \: \\ 10x = 120 \\ x = 12 \\ put \: x = 12 \: in \: eqation \: 1 \\ \\ 12(12) - y = 110 \\ 144 - y = 110 \\ - y = 110 - 144 \\ - y = - 34 \\ y = 34$
please mark my answer as brainliest

Answer 2

answer- x=12. y=34.....

hope plz do ur own process.......becoz there is some trouble......