Question

10 years ago father was 12 times as old as his son and 3 years hence he will be twice as old as his son . find their present ages

Answer 1

let the age of the son be x and the father be y.
eq.1 ⇒ y-10 = 12(x-10)
⇒12x-y = 110
eq.2 ⇒ y+3 = 2(x+3)
⇒2x-y = -3
subtracting eq.2 feom eq.1
⇒10x = 113
x = 11.3 years
y = 25.6 yeas