10 years ago father was six times as older as his daughter after 10 years he will be to is as old as his daughter determined their present age
Answers
Let the father's age = X
Let the father's age = X daughter's age be =Y
→10 years ago father was 6 times as older as his daughter.
i.e, age of father 10 years ago = X - 10
i.e, age of father 10 years ago = X - 10 age of daughter 10 years ago = Y- 10
According to question..
→ (X - 10) = 6(y - 10)
→ (X - 10) = 6(y - 10)→ ( X - 10) = 6Y - 60
→ (X - 10) = 6(y - 10)→ ( X - 10) = 6Y - 60→ X - 6Y = -60 + 10
→ (X - 10) = 6(y - 10)→ ( X - 10) = 6Y - 60→ X - 6Y = -60 + 10→ X - 6Y = -50…….……(1)
THERE IS SOME MISTAKE IN QUESTION IN AFTER 10 YEARS.....
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IF YOUR QUESTION IS CORRECT I CAN EASILY SOLVE IT BEACUSE I ALREADY MAKE AN EQUATION .
Answer:
Let the present age of father and his daughter are X and Y respectively given that 10 years ago a father was six time as old as his daughter
(x-10) = 6(y-10)
= x - 10 = 6y - 60
= x - 6y + 50 = 0........ 1
Step-by-step explanation:
Also given that after 10 years, he will be twice as old as his daughter
(x + 10 ) = 2 ( y + 10 )
= x - 10 = 2y + 20
= x -2y - 10 = 0..........2
Subtracting equation ( 1) from ( 2), we have
x - 2y - 10 - (x + 6y - 50 = 0
= x - 2y - 10 - x + 6y - 50 = 0
= 4y - 60 = 0
= y = 15
Substituting the value of y in equation ( 2 ), we have
x - 2 * 15 - 10 =0
= x - 30 -10 = 0
= x = 40
Hence, the present age of father and his daughter is 40 and 15 respectively
There for sum of their present age = x + y
= 40 + 15
= 55
Hence, the correct answer is 55