10 years ago the age of a father was 4 times of his son. 10 years hence the age of the father will be twice that of his son
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let the age of son be x and fThers age be y
10 years ago
age of son =x-10
age of father=y-10
y-10=4(x-10)......(1)
(y+10)=2(x+10)
solve these equations you will get ans
10 years ago
age of son =x-10
age of father=y-10
y-10=4(x-10)......(1)
(y+10)=2(x+10)
solve these equations you will get ans
saurabhsemalti:
but I don't ans is coming
I don't think
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