Question

10 years ago the age of a father was four times of his son ten years hence the age of father will be the twice of that of his son the present age of father and son are​

Answer 1

Answer:

Son's present age=20yrs

Father's present age=50yrs

Step-by-step explanation:

Let the age of son(10 yrs ago) be x yrs.

10 yrs ago

son's age=x

father's age=4x

After 10 years

son's age=x+20

father's age=4x+20

A.T.Q.

4x+20=2(x+20)

4x+20=2x+40

4x-2x=40-20

2x=20

x=20/2

x=10

Present age of

son=x+10

=10+10

=20yrs

father=4x+10

=4(10)+10

=40+10

=50yrs

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Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20