Question

10 years ago the age of a father was four times of his son.ten years from now the age of the father will be double that of his son.what are the present age of the father and son?

Answer 1

hey there !!!

Let us suppose son’s age to be X and father age to be Y.

10 years ago, son’s age (X-10) and father’s age (Y-10)

According to the question, Ten years ago the age of the father was four times the age of his son

Hence, 4(X-10)=Y-10

=>4X-40=Y-10

=>Y=4X-30 or 4X-Y=30 ………………………eq(i)

10 years hence, son’s age (X+10) and father’s age (Y+10)

According to the question, Ten years hence the age of the father will be twice that of his son

Hence, 2(X+10)=Y+10

=> 2X+20=Y+10

=>Y=2X+10 …………………………………..eq(ii)

Both eq(i) and eq(ii) gives father’s present age , now we can just avaluate them

i.e 4X-30=2X+10

=>4X-2X=10+30

=>2X=40

=>X=20 i.e son’s present age is 20 years

to get father’s age we can put X value either in eq(i) or eq(ii)

Y=2(20)+10 = 50 Years

There you go

Father’s present age 50 and son’s present age 20

hope it helps !!!

Answer 2

Hope this helped. Please mark as brainliest