Question

10 years ago the age of father 3.5times more than the age of his son and after 10 years the age of father will 2.5 times more than age of his son find the sum of present age of father and son

Answer 1

Step-by-step explanation:

Let, the

PRESENT AGES BE:

Father's age be 'x'

son's age be 'y'

Given,

10 years ago the age of father 3.5times more than the age of his son

x-10=3.5(y-10)

x-3.5y+25=0. _1

Also given,

after 10 years the age of father will be 2.5 times more than age of his son

x+10=2.5(y+10)

x-2.5y=15. _2

subtracting equations 1&2 we get,

-y=-40

y=40

substituting value of y in

equation 2.we get,

x-2.5(40)=15

x-100=15

x=115

the sum of present age of father and son is x+y i.e 115+40=155