Question

10 years ago ,the age of father was four times the age of his son then. 10 year hence ,the age of father will be twice the age of his son. find the present ages​

Answer 1

Answer:

father age is 50

son age is 20

Step-by-step explanation:

check above for step by step explanation

Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20