Question

10 years ago the age of man was 20 years less than 6 times his son's age. 10 years hence, his age will be 30 yrs less than thrice his son's age after how many years from the their combined age in 90 years


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Answer 1

Step-by-step explanation:

Five years hence, father's age will be three times the age of his son. Five years ago, father was seven times as old as his son. Find their present ages

Answer 2

Step-by-step explanation:

Let the father present age =x years and son present age =y years

According to the first condition

5 years later father will be (x+5) years old and son will be (y+5) years old.

⇒x+5=3(y+5)

⇒x+5=3y+15⇒x=3y+10....eq1

According to the second condition

5 years ago father was (x−5) years old and son was (y−5) years old.

⇒x−5=7(y−5)

⇒x−5=7y−35

⇒x−7y=−30....eq2

Put the value of x from eq1

⇒3y+10−7y=−30⇒−4y=−40⇒y=10

Put y=10 in eq1

⇒x=3×10+10=40

Hence, Father present age =40 years

Son present age =10 years