10 years ago the age of son and father is in the ratio5:8. After 10 year the ratio of their age will become 7:9. Find the present age
Answers
Let 10 years ago,
Age of the son = 5x years
Age of the father = 8x years
After 10 years,
Age of son = Age 10 years ago + 20 years
= ( 5x + 20 ) years
Age of father = Age 10 years ago + 20 years
= ( 8x + 20 ) years
According to the question : -
Ratio of ages become 7 : 9
( 5x + 20 ) : ( 8x + 20 ) = 7 : 9
9( 5x + 20 ) = 7( 8x + 20 )
45x + 180 = 56x + 140
180 - 140 = 56x - 45x
40 = 11 x
40 / 11 = x
Therefore,
Present age of son : 5x + 10 years
⇒ 5( 40 / 11 ) + 10 years
⇒ 200 / 11 + 10 years
⇒ ( 200 + 110 ) / 11 years
⇒ 310 / 11 years
Present age of father = 8x + 10 years
⇒ 8( 40 / 11 ) + 10 years
⇒ 320 / 11 + 10 years
⇒ ( 320 + 110 ) / 11 years
⇒ 430 / 11 years