Math, asked by OoJii20, 4 months ago

10 years ago the average age of a family of 4 members was
24 years. Nowtwo more babies were born with age difference
of 2 years and average age of the family is still 24. What is
the present age of the youngest child?
(a) 4 years
(6) 6 years
c) 3 years
(d) 5 years​

Answers

Answered by AabhashBhowmick
2

Answer:

option a)

Step-by-step explanation:

hope it helped

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Answered by sans2121
1

Answer:

The correct iption is (c) 3 years.

Please mark my answer brainliest.

Step-by-step explanation:

Present total age of 4 members =24×4=96+(10×4)=136

Preset total age of 6 members (including 2 children) =24×6=144

So sum of the ages of the two children =144−136=8 yrs.

Thus the ages of the children will be 5 yrs and 3 yrs.

As (5+3=8 and 5−3=2)

So, the youngest child's age is 3 years old.

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