10 years ago the average age of a family of 4membersr was 24, in the meantime, two children born by a gap of two yrs, what is the age of younger child if the average age family is same as it was 10 years ago.
Answers
Answered by
15
THANKS FOR THE QUESTION !
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ANS :
........................ 3 YRS ......................
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GIVEN :
=> 10 YRS AGO :
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NO. OF FAMILY MEMBERS :
=> 4
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AVERAGE OF AGES :.
=> 24 YRS
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10 YRS AGO :
=> THE SUM OF AGES OF ALL FAMILY MEMBERS :
=> NO. OF MEMBERS * AVERAGE
=> 4 * 24
=> 96
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AT PRESENT :
=> THE SUM OF AGES OF 4 FAMILY MEMBERS :
=> 10 * NO. OF MEMBERS + PREVIOUS SUM
=> 10 * 4 + 96 YRS
=> 40 + 96 YRS
=> 136 YRS
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CONDITION :
=> IN BETWEEN GAP :
=> 2 BABIES BORN BY A GAP OF 2 YRS
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TOTAL FAMILY MEMBERS NOW ,
=> 4 + 2
=> 6
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STILL THE AVERAGE IS SAME :
=> AS PER THE AVERAGE BEFORE 10 YRS
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SUM OF AGES OF ALL FAMILY MEMBERS NOW,
=> NO. OF MEMBERS * AVERAGE
=> 6 * 24 YRS
=> 144 YRS
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TO FIND :
=> AGE OF SMALLER CHILD
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SUM OF AGES OF 2 CHILDREN :
=> SUM OF AGES OF ALL 6 FAMILY MEMBERS - SUM OF AGES OF 4 FAMILY MEMBERS
=> 144 - 136
=> 8 YRS
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LET,
=> THE AGE OF THE SMALLER CHILD BE :
=> X
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2 YRS AGO BIGGER CHILD WAS BORN :
=> SO, AGE OF BIGGER CHILD :
=> X + 2 YRS
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BUT THE SUM OF AGES OF 2 CHILDREN :
=> 8 YRS
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ACCORDING TO INFO :
=> X + X + 2 YRS = 8 YRS
=> 2X + 2 YRS = 8 YRS
=> 2X YRS. = 8 YRS - 2 YRS
=> 2X YRS = 6 YRS
=> X YRS = 6 / 2 YRS
=> X = 3 YRS
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SO,
=> THE AGE OF YOUNGER CHILD IS X YRS
=> MEANS
=> ...................... 3 YRS ........................
_______________________________
HOPE IT WILL HELP U ......
THANKS AGAIN.........
_______________________________
______________________________
ANS :
........................ 3 YRS ......................
______________________________
GIVEN :
=> 10 YRS AGO :
_______________________________
NO. OF FAMILY MEMBERS :
=> 4
_______________________________
AVERAGE OF AGES :.
=> 24 YRS
______________________________
10 YRS AGO :
=> THE SUM OF AGES OF ALL FAMILY MEMBERS :
=> NO. OF MEMBERS * AVERAGE
=> 4 * 24
=> 96
_______________________________
AT PRESENT :
=> THE SUM OF AGES OF 4 FAMILY MEMBERS :
=> 10 * NO. OF MEMBERS + PREVIOUS SUM
=> 10 * 4 + 96 YRS
=> 40 + 96 YRS
=> 136 YRS
_______________________________
CONDITION :
=> IN BETWEEN GAP :
=> 2 BABIES BORN BY A GAP OF 2 YRS
______________________________
TOTAL FAMILY MEMBERS NOW ,
=> 4 + 2
=> 6
______________________________
STILL THE AVERAGE IS SAME :
=> AS PER THE AVERAGE BEFORE 10 YRS
______________________________
SUM OF AGES OF ALL FAMILY MEMBERS NOW,
=> NO. OF MEMBERS * AVERAGE
=> 6 * 24 YRS
=> 144 YRS
_______________________________
TO FIND :
=> AGE OF SMALLER CHILD
_______________________________
SUM OF AGES OF 2 CHILDREN :
=> SUM OF AGES OF ALL 6 FAMILY MEMBERS - SUM OF AGES OF 4 FAMILY MEMBERS
=> 144 - 136
=> 8 YRS
_______________________________
LET,
=> THE AGE OF THE SMALLER CHILD BE :
=> X
______________________________
2 YRS AGO BIGGER CHILD WAS BORN :
=> SO, AGE OF BIGGER CHILD :
=> X + 2 YRS
______________________________
BUT THE SUM OF AGES OF 2 CHILDREN :
=> 8 YRS
______________________________
ACCORDING TO INFO :
=> X + X + 2 YRS = 8 YRS
=> 2X + 2 YRS = 8 YRS
=> 2X YRS. = 8 YRS - 2 YRS
=> 2X YRS = 6 YRS
=> X YRS = 6 / 2 YRS
=> X = 3 YRS
______________________________
SO,
=> THE AGE OF YOUNGER CHILD IS X YRS
=> MEANS
=> ...................... 3 YRS ........................
_______________________________
HOPE IT WILL HELP U ......
THANKS AGAIN.........
_______________________________
Answered by
4
Answer: The required age of the younger child is 3 years.
Step-by-step explanation: Given that 10 years ago, the average age of a family of 4 members was 24. In the meantime, two children born by a gap of two yrs.
We are to find the age of the younger child if the average age of the family is same as it was 10 years ago.
Let x years be the age of the younger child and let S be the sum of the ages of the members of the family before 10 years.
Then, according to the given information, we have
Therefore, the present average age of the family is given by
.
Thus, the required age of the younger child is 3 years.
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