Math, asked by sohail8844, 10 months ago

10 years ago the average age of a family of 4membersr was 24, in the meantime, two children born by a gap of two yrs, what is the age of younger child if the average age family is same as it was 10 years ago.

Answers

Answered by shreya32457
15
THANKS FOR THE QUESTION !

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ANS :

........................ 3 YRS ......................

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GIVEN :

=> 10 YRS AGO :

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NO. OF FAMILY MEMBERS :

=> 4

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AVERAGE OF AGES :.

=> 24 YRS

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10 YRS AGO :

=> THE SUM OF AGES OF ALL FAMILY MEMBERS :

=> NO. OF MEMBERS * AVERAGE

=> 4 * 24

=> 96

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AT PRESENT :

=> THE SUM OF AGES OF 4 FAMILY MEMBERS :

=> 10 * NO. OF MEMBERS + PREVIOUS SUM

=> 10 * 4 + 96 YRS

=> 40 + 96 YRS

=> 136 YRS

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CONDITION :

=> IN BETWEEN GAP :

=> 2 BABIES BORN BY A GAP OF 2 YRS

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TOTAL FAMILY MEMBERS NOW ,

=> 4 + 2

=> 6

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STILL THE AVERAGE IS SAME :

=> AS PER THE AVERAGE BEFORE 10 YRS

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SUM OF AGES OF ALL FAMILY MEMBERS NOW,

=> NO. OF MEMBERS * AVERAGE

=> 6 * 24 YRS

=> 144 YRS

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TO FIND :

=> AGE OF SMALLER CHILD

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SUM OF AGES OF 2 CHILDREN :

=> SUM OF AGES OF ALL 6 FAMILY MEMBERS - SUM OF AGES OF 4 FAMILY MEMBERS

=> 144 - 136

=> 8 YRS

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LET,

=> THE AGE OF THE SMALLER CHILD BE :

=> X

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2 YRS AGO BIGGER CHILD WAS BORN :

=> SO, AGE OF BIGGER CHILD :

=> X + 2 YRS

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BUT THE SUM OF AGES OF 2 CHILDREN :

=> 8 YRS

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ACCORDING TO INFO :

=> X + X + 2 YRS = 8 YRS

=> 2X + 2 YRS = 8 YRS

=> 2X YRS. = 8 YRS - 2 YRS

=> 2X YRS = 6 YRS

=> X YRS = 6 / 2 YRS

=> X = 3 YRS

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SO,

=> THE AGE OF YOUNGER CHILD IS X YRS

=> MEANS

=> ...................... 3 YRS ........................

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HOPE IT WILL HELP U ......

THANKS AGAIN.........

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Answered by ColinJacobus
4

Answer:  The required age of the younger child is 3 years.

Step-by-step explanation:  Given that 10 years ago, the average age of a family of 4 members was 24. In the meantime, two children born by a gap of two yrs.

We are to find the age of the younger child if the average age of the family is same as it was 10 years ago.

Let x years be the age of the younger child and let S be the sum of the ages of the members of the family before 10 years.

Then, according to the given information, we have

\dfrac{S}{4}=24\\\\\Rightarrow S=96~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Therefore, the present average age of the family is given by

\dfrac{S+4\times10+x+x+2}{6}=24\\\\\\\Rightarrow S+40+2x+2=144\\\\\Rightarrow 96+40+2x+2=144~~~~~~~~~~~~~~~~~~~~~[\textup{Using (i)}]\\\\\Rightarrow 2x+138=144\\\\\Rightarrow 2x=144-138\\\\\Rightarrow 2x=6\\\\\Rightarrow x=\dfrac{6}{2}\\\\\Rightarrow x=3..

Thus, the required age of the younger child is 3 years.

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