Question

10 years ago the sum of the ages of two sons was one third of his father's age one son is two years older than the other and the sum of their present ages is 14 years less than the father's present age find the present ages of all

Answer 1

this answer will be solved by using ratio
the sum of the age of both son = 14
10+14= 24-2=22
may be it's right
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Answer 2

hi


22 is answer

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