Question

10 years back, the sum of the ages of a mother and her daughter was 45.if the retio of their present ages be 9:4, then the present age of the daughter is ​

Answer 1

Let the Ages of Mother and her daughter be 'x'

We will write the ratio as 9/4

So,According to the Question

10 years Ago sum of there was 45

Therefore,

9x-10/4x-10=45

By Cross Multiplication we have,

9x-10 × 1 = 45(4x-10)

=9x-10= 180x-450

Now by Transposing Method

=-10+450=180-9x

=440=171x

=440/-171= x

Hence,The answer is -440/171

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