Math, asked by mohitagangisetty, 3 months ago

10 years before the ages of a mother and her daughter were in the ratio 3 is to one another 10 years from now the ratio of their ages will be 13 is to 7 what are present ages​

Answers

Answered by jeevanmunegowd7
1

Answer:

HI GUYS.PLEASE MARK ME AS BRAINLIST

Step-by-step explanation:

Let the mother's age be 7x and her daughter's be 2x (5 years ago)

after 10 years from present

(7x+15)/2 = 2x+15

7x+15 =4x+30

3x = 15

x=5

Their present ages are

Mom =7*5+5 =40

daughter = 2*5+5 =15  

Similar questions