10 years before, the ages of a mother and her daughter were in the ratio 3: 1. On another 10 years from now, the ratio of their ages will be 13: 7. What are their present ages?
Answers
Answer:
) 27 yr
Description for Correct answer:
Let the ages of A and B 10 yr before were 13x yr and 17x yr, respectively.
Then, present age of A = 13x + 10 and present age of B = 17x + 10
According to the question,
\( \large\frac{13x + 10 + 17}{17x + 10 + 17} = \frac{10}{11} \)
\( \large\frac{13x + 27 }{17x + 27} = \frac{10}{11} \)
Hence, present age of B = 17 x 1 + 10 = 27yr
Part of solved Problem on ages questions and answers : >> Aptitude >> Problem on ages
Step-by-step explanation:
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Answer:
let mother's age before 10 years be 3x and daughter's age be x.
at present
mother's age = 3x+10
daughter's age = x+10
after 10 years
mother's age = 3x+20
daughter's age = x+20
by question their age will be in ratio 13:7
therefore, 3x+20/x+20 = 13/7
= 7(3x+20) = 13(x+20)
= 21x+140 = 13x+260
= 21x-13x = 260-140
= 8x = 120
= x = 120/8 = 15
therefore mother's present age = 3x +10
= 3*15+10 = 55 years
daughter's present age = x+10 = 25 years