Question

10 years Hence a man's age will be twice the age of his son 10 years ago the man was four times as old as his son find their present ages

Answer 1

Define x:

Let the son's age be x

Son = x

Man = 2x

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10 years ago:

Son = x - 10

Man = 2x - 10

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The man was 4 times as old as his son:

2x - 10 = 4 (x - 10)

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Solve x:

2x - 10 = 4 (x - 10)

2x - 10 = 4x - 40

4x - 2x = 40 - 10

2x = 30

x = 15

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Find their age:

Son = x = 15

Father = 2x = 2(15) = 30

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Answer: The son is 15 years old and the father is 30 years old.

Answer 2

Here is your answer user.