10 years hence , the age of x will be 2 times that of age of y , 10 years ago , the age of x was six times that of age of y . what are their present ages ?
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Answer:x=40 and y=15
Step-by-step explanation:
Let present age is x,y then from question
x-10=6(y-10). (i)
x+10=2(y+10). (ii)
Solve this
from equ. (ii)
x=2y+10
On putting this in equ. first we get
Y= 15 and X = 40
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