Question

10 years later a will be twice as old as B five years ago a was three times as old as B what are the present ages of a and b
Step by step explanation will be the brainiest answer​

Answer 1

Answer:

A is 50 and B is 20

Step-by-step explanation:

Lets assume their present ages as A and B

10 years later,

A will be 10 years older ==> A + 10

B will also be 10 years older ==> B + 10

Given ( 10 years later A will be twice as old as B)

i.e.  A + 10 = 2 ( B + 10) ;

      A + 10 = 2B + 20 ;

      A = 2B + 20 -10 ;

      A = 2B + 10;                                               (Equation 1)

Also Given ( 5 years ago A was 3 times as old as B)

5 years earlier,

A will be 5 years younger ==> A - 5

B will also be 5 years younger ==> B - 5

i.e. A - 5 = 3 ( B - 5) ;                                        (Equation 2)

Substituting (1) in (2)

2B + 10 - 5 = 3B - 15 ;

2B + 5 = 3B - 15 ;

15 + 5 =3B - 2B ;

B = 20 ;

Hence B = 20;

Since we know B, we can substitute it in Equation 1 and find A

A = 2B + 10;

A = 2 x 20 + 10;

A = 40 + 10;

A = 50;

Therefore, the present ages of A is 50 and B is 20

Hope it helped you, May you do well for your exams........