Question

10 yrs ago father was 12 times as old as his son and 10 yrs hence he will be twice as old as his son will be then find their present ages

Answer 1

Step-by-step explanation:

Answered

Ten year ago father was 12 times as old as his son and 10 year hence, he will be twice as old as his son , find their present age by subsutution methods----

Let fathers age=x

let sons age=y

fathers age before 10 yrs= x-10

sons age before 10 yrs=y-10

according to question,

x-10=12(y-10)

x=12y-120+10

x=12y-110-----(1)

age of father after 10yrs=x+10

age of son after 10 yrs=y+10

according to question,

x+10=2(y+10)

x+10=2y +20

subsitituting (1)

12y-110+10=2y+20

12y-100=2y+20

12y-2y=20+100

10y=120

y=120/10

y=12

therefore,x= 12y-110

x=12(12)-110

x=144-110

x= 34