100.0 g of 4.0°C water is heated until its temperature is 37°C. If the specific heat of water is 4.18 J/g°C, calculate the amount of heat energy needed to cause this rise in temperature.
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Answer:
13.794 kJ
Explanation:
Given :
Mass m = 100 g
Temperature difference Δ T = 37 - 4 = 33 C
Specific heat c = 4.18 J / g C
We have to find heat energy Q :
We know :
Q = m c Δ T
Putting values here we get :
Q = ( 100 × 4.18 × 33 ) J
= > Q = ( 418 × 33 ) J
= > Q = 13794 J
= > Q = 13.794 kJ
Therefore , we get required answer.
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