Question

(100.1)² find using identity 2 step by step​

Answer 1

Answer:

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Secondary School Math 5 points

Evaluate the value of (101)² by using suitable identity

Ask for details Follow Report by Eabhiram2000 13.10.2018

Answers

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We will use an identity which is quite often used by you in algebra.

( a + b ) ^ 2 = a ^ 2 + b ^ 2 + 2ab

Given,

( 101 ) ^ 2

If we split the given value correctly then,

( 100 + 1 ) ^ 2

Now,

a = 100 and b = 1

Therefore,

( 101 ) ^ 2 = ( 100 ) ^ 2 + ( 1 ) ^ 2 + 2 * 100 * 1

( 101 ) ^ 2 = 10000 + 1 + 200

On performing simple addition we get,

( 101 ) ^ 2 = 10,201

Therefore,

Your answer is 10,201.

Using identities for such calculations helps us to find the answer quickly and more correctly as performing normal multiplication may cause certain errors.

Answer 2

The value of $(100.1)^2$ is equal to 10020.01.

Step-by-step explanation:

We have,

$(100.1)^2$

To find, the value of $(100.1)^2$ = ?

∴ $(100.1)^2$

$=(100+0.1)^2$

Using the algebraic identity,

$(a+b)^2=a^{2} +2ab+b^2$

Here, a = 100 and b = 0.1

= $100^2$ + 2(100)(0.1) + $0.1^2$

= 10000 + 200(0.1) + 0.01

= 10000 + 20 + 0.01

= 10020 + 0.01

= 10020.01

∴ The value of $(100.1)^2$ = 10020.01

Thus, the value of $(100.1)^2$ is equal to 10020.01.