Question

100-100/100-100=2
Prove that

Answer 1

HERE is ur ans


We have (100–100)/(100–100)

We can write 100 as 10^2.

So, (100-100)=(10^2 - 10^2) in the numerator.

In the denominator, we can write 100–100 = 10 * (10–10).

So, that will make (100–100)/(100–100) = (10^2 – 10^2)/ [10 * (10–10)].

We know that a^2 - b^2 can be written as (a+b)*(a-b) and I’m applying this rule to (10^2 - 10^2), neglecting the fact that both a and b are 10 here.

So, we get (10^2 - 10^2)/[10 * (10–10)] = [(10+10)*(10–10)] / [10*(10–10)].

Cancelling 10–10 in the numerator and denominator. This is not actually possible in mathematics, but here we are not simplifying it to 0/0.

Now, we have [(10+10)*(10–10)] / [10*(10–10)] = (10+10)/10 = 20/10 = 2.

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