Question

100-[121p^2-88pq 16q^2]
factorise using splitting the middle term

Answer 1

Step-by-step explanation:

$100 - (121 \ {p}^{2} - 88pq \: + 16 {q}^{2}) \\ = 100 - (121{q}^{2} - 44pq - 44pq + 16 {q}^{2} ) \\ = 100 - (11q(11q - 4p) )\: 4q( - 11p + 4q)$

$100 - {(11q + 4q)( - 11pq + 4pq)}$

Hope it helps you...