Question

100
78. For what value of n, the sum of digits
the number (10" + 1) is 2?
(a) For n = 0 only
(b) For any whole number n
(c) For any positive integer n only
(d) For any real number n
HGY-KUV/59C​

Answer 1

We know that any number of the form 10n−1 is 9999...n times.

The sum of the digits is 9+9+9+...n times =3798

=>9n=3798=>n=422

Thus, the value of n is 422 .