Math, asked by arshpeetff690, 4 days ago

100+79+57+433-78+890-300= ?

Answers

Answered by upendra7382
1

Answer:

100+79+57+433−78+890−300

Add 100 and 79 to get 179.

179+57+433−78+890−300

Add 179 and 57 to get 236.

236+433−78+890−300

Add 236 and 433 to get 669.

669−78+890−300

Subtract 78 from 669 to get 591.

591+890−300

Add 591 and 890 to get 1481.

1481−300

Subtract 300 from 1481 to get 1181.

1181

Step-by-step explanation:

Answered by divyapakhare468
0

To solve : 100+79+57+433-78+890-300

Solution:-

  • To solve the above equation we will follow BODMAS rule.
  • It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.
  • Where,  

                 $$\begin{array}{l}\\B=brackets\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { Division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$$

  • According to above rule we will solve .100+79+57+433-78+890-300

        = 1181

Hence , value of 100+79+57+433-78+890-300 is 1181 .

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