100×96 using a suitable indentit
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Answered by
0
Hello Mate!
This question can be solved by using identity :
( a + b )( a - b ) = a^2 - b^2,
Here, in 100 × 96 :-
( 98 + 2 ) ( 98 - 2 ) = 98^2 - 2^2
Now lets solve 98^ 2 also by identity ( a - b )^2
= a^2 + b^2 - 2ab
( 100 - 2 )^2 = 100^2 + 2^2 - 2 ( 100 )( 2 )
= 10000 + 4 - 400
= 9604
So, 98^2 - 2^2 = 9604 - 4 = 9600
Hope it helps☺!✌
This question can be solved by using identity :
( a + b )( a - b ) = a^2 - b^2,
Here, in 100 × 96 :-
( 98 + 2 ) ( 98 - 2 ) = 98^2 - 2^2
Now lets solve 98^ 2 also by identity ( a - b )^2
= a^2 + b^2 - 2ab
( 100 - 2 )^2 = 100^2 + 2^2 - 2 ( 100 )( 2 )
= 10000 + 4 - 400
= 9604
So, 98^2 - 2^2 = 9604 - 4 = 9600
Hope it helps☺!✌
Answered by
0
No identity will be used
≈≈≈≈≈≈≈≈≈≈≈≈≈
""" "" """"""""""""""""""
The answer is
9600
But here we can use as :-|
(a+b) (a-b)
(98+2)(98-2)
98^-2^
9600
Hope it helps u
≈≈≈≈≈≈≈≈≈≈≈≈≈
""" "" """"""""""""""""""
The answer is
9600
But here we can use as :-|
(a+b) (a-b)
(98+2)(98-2)
98^-2^
9600
Hope it helps u
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