Question

100-a^2-b^2-2ab factorise it anyone fast pls I will mark u as brainliest

Answer 1

Solution -

♦ 100 - a² - b² - 2ab

= (10)² - (a² + b² + 2ab)

= (10)² - (a + b)²

= [10 + (a + b)] [10 - (a + b)

= (10 + a + b) (10 - a - b)

Answer - (10 + a + b) (10 - a - b)


Identity Used -

♢ a² + b² + 2ab = (a + b)²

♢ a² - b² = (a + b) (a - b)

Note -

(10)² = 100

Answer 2

Answer:

Step-by-step explanation:100-a^2-b^2-2ab=[take 100=10^2 añd take out the minus(-) as common]

10^2-(a^2+b^2+2ab)=[convert the bracket portion to the identity a^2+b^2]

10^2-(a^2+b^2)=[now with identity a^2-b^2 continue it]

(10+a+b)(10-(a+b))=

(10+a+b)(10-a-b) :--ANSWER