Question

100. A invested 20% more than B. B invested 25% less than C. If the total sum of their investment is Rs. 2650, how much amount did 'B' invest?

(A) Rs. ୨00
(B) Rs. 750
(C) Rs. 134
(D) Rs. 1000​

Answer 1

Given:

A invested 20% more than B. B invested 25% less than C. If the total sum of their investment is Rs. 2650,

Solution:

Assume that the investment of C is $\[100x\]$.

Know that B invested 25% less than C.

Therefore B invested  

$\[\begin{array}{l} = 100x - 100x \times \frac{{25}}{{100}}\\ = 75x\end{array}\]$

Know that A invested 20% more than B,

Therefore,

$\[\begin{array}{l} = 75x + 75x \times \frac{{20}}{{100}}\\ = 90x\end{array}\]$

Know that sum of their investment is Rs. 2650,

$\[\begin{array}{l}100x + 75x + 90x = 2650\\ \Rightarrow 265x = 2650\\ \Rightarrow x = 10\end{array}\]$

Therefore investment of B is,

$\[\begin{array}{l} = 75 \times 10\\ = Rs.750\end{array}\]$

Hence the B's investment is 750 rupees.

Answer 2

Given :  A invested 20% more than B.

B invested 25% less than C

the total sum of their investment is Rs. 2650,

To Find : how much amount did 'B' invest

(A) Rs. ୨00

(B) Rs. 750

(C) Rs. 134

(D) Rs. 1000​

Solution:

Let say A , B and C invested  A , B and C Rs Respectively

A invested 20% more than B.

=> A = (20/100)B + B  = 1.2B

B invested 25% less than C

=>  B = C - (25/100)C

=> B = 3C/4

=> C = 4B/3

A + B + C = 2650

=> 1.2B + B + 4B/3 = 2650

=> 2.2B + 4B/3 = 2650

=> 6.6B + 4B  = 2650 * 3

=> 10.6B = 2650 * 3

=> B =  750

Amount invested by B = Rs 750

Option B) Rs 750

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