Question

100 cells each of emf 5V and internal
resistance 1 ohm are to be arranged so as
to produce maximum current in a 25 ohm
resistance. Each row contains equal number of cells.the number of rows should be
A)2 B)4 C)5 D)100​

Answer 1

Answer:

Correct option (a) 2

Explanation:

Total no. of cells, = mn = 100

Current will be maximum when R = nr/m; 25 = n x 1/m

⇒ n = 25 m

From equation (i) and (ii)

n = 50 and m = 2

Explanation:

Hope it helps!

Answer 2

Let m be the number of rows and n be the number of cells of each rows.

Thus, mn=100⇒n=100/m

For Max current I=  nr/m

​or I=  100r/m2

​or m  2 = 100×1 /25

=4⇒m=2