Question

100 cells each of emf 5V and internal resistance 1ohm are to be arranged so as to resistance. Each row contains equal number of cells. The number of rows should be​

Answer 1

Answer: Let m be the number of rows and n be the number of cells of each rows.

Thus, mn=100⇒n=100/m

For Max current I=  

m

nr

​

 

or I=  

m  

2

 

100r

​

 

or m  

2

=  

25

100×1

​

=4⇒m=2Let m be the number of rows and n be the number of cells of each rows.

Thus, mn=100⇒n=100/m

For Max current I=  

m

nr

​

 

or I=  

m  

2

 

100r

​

 

or m  

2

=  

25

100×1

​

=4⇒m=2