100 cm3 of 1m ch3cooh was mixed with 100 cm3 of 2m ch3oh to form an ester. The change in the initial rate if each solution is diluted with equal volume of water would be:
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100 cm3 of 1m ch3cooh was mixed with 100 cm3 of 2m ch3oh to form an ester. The change in the initial rate if each solution is diluted with equal volume of water would be:
Explanation:
R=k[CH ₃ COOH][C 2 H 5 OH]
Initial rate: R₁ =k(a)(b)
The final : R ₂ =k( a/2 )( b/2 )
( R ₁/ R ₂ )= [k(a/2)(b/2)] / [k(a)(b)]
= [ab [ab/4]/[ab ]= 1/4
R ₁ / R ₂
=0.25
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