Question

100 cm3 of solution of protein contains 0.63 g of protein.If the osmotic pressure at 300 kelvin is 2.57x10^3 the molar mass of protein

Answer 1

Given that

V = 100 cm³,0.1L

π=2.57×10³

T=300K

w=0.63g

M=?

We know that

π=CRT

π=wRT/VM

2.57×10³=(0.63×0.0821×300)/M×0.1

M=(0.63×0.0821×300)/(0.1×2.57×10³)

M= 0.060377 g/mol. Anshwer

Answer 2

Answer:

Molar mass of protein is 61,039g/mol.

Explanation:

Molar mass of a substance is the mass in grams of one mole of the compound.

In a substance, the amount of entities present e.g. atoms, molecules, ions, is defined as a mole. A mole of any substance is $6.022\times10^{23}$ molecules.

The standard unit for Molar mass is gram/mol.

Mole Definition

In chemistry, the mole is a fundamental (SI) unit used to measure the amount of substance. This quantity is sometimes referred to as the chemical amount.

A substance is something that has mass and occupies space. The molar mass/molecular weight is actually the sum of the total mass in grams of the atoms present to make up a molecule per mole.

Mass of protein, $W=0.63g$

Volume of solution,$V=100cm^{3}$

Temperature of solution,$T=300K$

Osmotic Pressure,$\pi =2.57\times10^{3}$

Osmotic Pressure,$\pi =CRT=\frac{n}{V} RT$

$\pi =\frac{W/M}{V}\times RT$

$\pi =\frac{W\times RT}{V\times \pi }$

$\pi =\frac{0.63\times0.083\times300}{0.1\times2.57\times10^{-3} }$

$\pi =61,039g/mol$

Therefore, Molar mass of protein is 61,039g/mol.

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