Question

100
find quaduatic polynomial, whose Sum
and product of its zeroes are 1/4
and-I​

Answer 1

Answer:

$4 {x}^{?} - x - 1 = 0$

Step-by-step explanation:

• $( \alpha + \beta )$ Given sum of zeroes = 1/4
• $( \alpha \beta )$product of zeroes = -1

according to the equation

${x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) = 0$

${x}^{2} - ( \frac{1}{4} )x + ( - 1) = 0$

$\\ taking \: lcm$

$\\ 4 {x}^{2} - x - 1 = 0$

so the answer is

$4 {x}^{2} - x - 1 = 0$

is the equation

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