Question

100 g caco3 ,is treated with 1 L of 1 N HCL ,what would be the weight of CO2 after completion of reaction

please tell me the solution please​

Answer 1

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100g of CaCO3 would be 1 mol because the molecular weight is 100.089. 1 L of 1M HCL would also be 1 mol of HCl, so in the reaction we can write CaCO3 + 2HCl --> CO2 + H2O+ CaCl2

so 1/2 mol of CO2 would come out of the reaction, which would be 22.005 grams because tahts the molecular weigt of CO2

Answer 2

100g of CaCO3 would be 1 mol because the molecular weight is 100.089. 1 L of 1M HCL would also be 1 mol of HCl, so in the reaction we can write CaCO3 + 2HCl --> CO2 + H2O+ CaCl2

so 1/2 mol of CO2 would come out of the reaction, which would be 22.005 grams because tahts the molecular weigt of CO2