Question

100 g ice at 0 °C is placed in 100 g water at 100 °C. The final temperature of the mixture will be ........... (Latent heat of melting of ice is 80 cal/g, and specific heat of water is 1 cal/g °C) (A) 10 °C (B) 20 °C (C) 30 °C (D) 50 °C

Answer 1

Answer:

10°C

Explanation:

100 g of ice at 0°C = 100g of water at 0°C needs 8000 cal

100 g of water at 100°C = 100 g water at 0°C gives 10000 cal

now we have 200 g water at 0°C and 2000 cal of heat available to increase temp of 200 g water , this heat will increase its temperature by 10°c