100 g of calcium carbonate reacts with hydrochloric acid to produce 111 g of calcium chloride, 18 g of water and 44 g of carbon dioxide. Calculate the amount of hydrochloric acid required for this reaction. [1] 1. 36.5 g 2. 73 g 3. 149 g 4. 63 g
Answers
Explanation: & Answer:
Write a balanced equation.
CaCO3+2HCl→CaCl2+CO2+H2O
Use the balanced equation to determine the mole ratios between CaCO3 and CaCl2 and between HCl and CaCl2 and between CaCO3 and HCl
Calcium carbonate and calcium chloride.
1 mol CaCO31 mol CaCl2 and 1 CaCl21 mol CaCO3
Hydrochloric acid and calcium chloride.
2 mol HCl1 CaCl2 and 1 mol CaCl22 HCl
Calcium carbonate and hydrochloric acid.
1 mol CaCO32 mol HCl and 2 mol HCl1 mol CaCO3
Determine the moles of each reactant by dividing the given masses by their molar masses.
28.0g CaCO3×1mol CaCO3100.1g CaCO3=0.280 mol CaCO3
12.0g HCl×1mol HCl36.5g HCl=0.329 mol HCl
Determine the mass of CaCl2 produced by each reactant by multiplying the moles of each reactant times the mole ratios with CaCl2 in the numerator. Then multiply the result by the molar mass of CaCl2