Question

100 g of hot water at 90°C is mixed to 400 g of cold water at 10°C, the equilibrium temperature of
the mixture is:​

Answer 1

Answer:

and is 26

Step-by-step explanation:

Heat transferred by hot water =ms∆T

=100g×s×[90]

heat gained by cold water=m's∆T'

=400g×s×[t-10]

Heat transferred by hot water =Heat gained by cold water

so,

100×s×[90-T]=400×s×[T-10]

90 -T =4(T-10)

90-T =4T-40

130=5T

T=26