Question

100 g of hydrochloric acid is added to 100 g zinc.
Find the volume of hydrogen gas evolved under
standard laboratory condition. (in L)​

Answer 1

Given:

100 g of hydrochloric acid is added to 100 g zinc.

To find:

Volume of Hydrogen gas produced in STP.

Calculation:

The reaction between HCl and Zn is as follows:

$\boxed{ \sf{2HCl + Zn \rightarrow ZnCl_{2} + H_{2}}}$

Moles of HCl = 100/36.5 = 2.73 moles

Moles of Zn = 100/65 = 1.53 moles

As per Reaction and available reagents , HCl is the limiting reagent.

So, we can say that :

2 moles HCl gives 22.4 L of H2 gas.

=> 2.73 moles of HCl gives

$= \dfrac{22.4}{2} \times 2.73 = 30.576 \: litres$

So, final answer is:

Volume of H2 gas is 30.576 Litres.

Answer 2

Explanation:

BY LIMITING REAGENTS

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