Question

100 g of water at 20°C is added to 100 g of ice at 0°C. The final temperature of mixture is

Answer 1

Explanation:

the final temperature of the mixture will be 20 degree centigrade , please mark it as BRAINLIEST

Answer 2

Answer:

Let the final temperature of the mixture be T.  

Then 100×80+100(T−0)×1/2100×80+100(T−0)×1/2  

(as specific heat of ice is 0.5cal/g/℃ and specific heat of water is 1cal/g∘C)  

=100×1×(100−T)

Solving, we get T=13.33℃

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