Question

100 gm of ice at 0°C is mixed with 10gm of steam at 100°C. Final mixture contains
a) only water at 0°C
b) only ice at 0°C
c) 90 gm of water and 20 gm of ice at 0°C
d) 90 gm of ice and 20 gm of water at 0°C
please answer ​

Answer 1

Answer:

B)

Explanation:

Latent heat of ice =m×l 100×80=8000Latent heat of steam =m×l =10×540 L.H of ice is greater than steam Specific heat of steam = mct =10×1×100=10005400+1000=6400 for steamCompositionQ=mlm=q/lm=6400/80m=80100-80=20g of ice 10+80=90g water