Question

100 GM of water at 30 degree Celsius is poured on a large block of ice at 0 degree Celsius.the mass of ice that melts is

for 50 points​

Answer 1

Answere:

100×30 = 3000/100 = 30

:. heat lost = heat gained

Answer 2

Answer:

According to thermodynamics,

Heat loss by water = heat gain by ice

It is given that,

Mass of water, m=80gm

Specific heat of water, s=1cal/gm/

0

C

So, heat lost by water during cooling fro 30

0

Cto 0

0

C

ΔH=msΔT

ΔH=80×1×(30−0)

ΔH=2400cal........(1)

Heat gain by ice, m

1

l=m

1

×80cal/gm.....(2)

Where, l is the latent heat of fusion

m

1

is the mass of ice melted.

From equation (1) and (2)

2400=80m

1

m

1

=30g

Hence, 30g of ice is melted.